# Law of cosines

### From Math Images

(→Solution) |
(→Solution) |
||

Line 91: | Line 91: | ||

<math>0 = \cos B </math> | <math>0 = \cos B </math> | ||

+ | |||

+ | Using [[inverse trig]], we know that | ||

+ | |||

+ | <math>B = 90^\circ </math> | ||

+ | |||

+ | And we can find the last angle measure <math>A</math> by subtracting the other two measures from <math> 180^\circ</math> | ||

+ | |||

+ | <math> 180^\circ - 90^\circ - 45^\circ = 45^\circ</math> | ||

+ | |||

+ | <math> A=45^\circ</math> |

## Revision as of 10:30, 30 May 2011

The law of cosines is a formula that helps in triangulation when two or three side lengths of a triangle are known. The formula relates all three side lengths of a triangle to the cosine of a particular angle.

When to use it: SAS, SSS.

## Contents |

## Proof

Let be oriented so that is at the origin, and is at the point.

### Distance Formula

is the distance from to .

Substituting the appropriate points into the distance formula gives us

Squaring the inner terms, we have

Since ,

Square both sides for

## Example Triangulation

Complete the triangle using the law of cosines.

### Solution

To find the side length ,

Simplify for

Since , substitution gives us

Simplify for

Taking the square root of both sides gives us

Now we can orient the triangle differently to get get a new version of the law of cosines so we can find angle measure ,

Substituting in the appropriate side lengths gives us

Simplify for

Subtracting from both sides gives us

Dividing both sides by gives us

Using inverse trig, we know that

And we can find the last angle measure by subtracting the other two measures from