Discussion:  All Topics 
Topic:  algebra 1 
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Subject:  RE: algebra 1 
Author:  Linda 
Date:  Jun 2 2004 
x2(1+ 1/x) = 6
x2 + x = 6
x2 + x 6 = 0
(x+3)(x2)=0
I believe the answer is x= 3 or x = 2
18x2y3z/3xyz = Divide numerator and denominator by 3
6x2y3z/xyz= Divide numerator and denominator by xyz
6 (2*3)= Multiply
6*6=36
m3  m=
m(m21)= Factor out m
m(M1)(m+1)
m= =1 or 1
x5 / x  x / x5
not sure about this one
5x + 5 / x+3 * 2x+6 / x2+2x+1 Factor and cancel
5(x+1)/x+3 * 2(x+3)/(x+1)(x+1)
5/1 * 2/x+1
10/x+1
not sure what the next step is
 
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