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Subject:   RE: optimization problem... Need help...
Author: Sandie
Date: Aug 1 2006
One solution where you would have 12 coins for a total of 71 would be as
follows:

     eight 5 unit coins = 40 units
     three 7 unit coins = 21 units
     one  10 unit coin  = 10 units
    ______________________________
   Twelve coins         = 71 units

Hope that helps.
  





On Aug  1 2006, Estelle001 wrote:
> Hi Danish...
no, I haven't found the right solution yet... Any help
> would be gratefull...
grtz
Estelle
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