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| Topic: | Difficult algorithm design; I could use some suggestions |
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| Subject: | RE: Difficult algorithm design; I could use some suggestions |
| Author: | Mathman |
| Date: | Aug 29 2006 |
Put this equal
> to A, the area, then rearrange, and eventually you wind up with a =
> 2[A/sqrt(3)]
Setting A = 256 [or whatever value you might need],
> then a = 24.314742
First let me say, I hate trying to type math in ASCII with a passion. In fact,
typing of any sort is not my first consuming interest in this life.
In any event, make that a = 2*sqrt[(A/sqrt(3)]
David.
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