Discussion:  Traffic Jam Applet tool 
Topic:  New Freind 
Related Item:  http://mathforum.org/mathtools/tool/10/ 
Post a new topic to the Traffic Jam Applet tool Discussion discussion 

Subject:  RE: New Freind 
Author:  Steve 
Date:  Apr 7 2004 
truth and knaves always lie?? If that's the case, then W and Y must be knights,
and the remainder must be knaves. I just experimented with each possible number
of knights, going from 0 up to 6.
On Apr 07, 2004, Kamali wrote:
Can anyone answer this easy deduction?!
You meet a group of people who speak to you as follows:
U says: none of us is a knight
V says: at least three of us are knights
W says: at most three of us are knights
X says: exactly five of us are knights
Y says: exactly two of use are knights
Z says: exactly one of us is a knight
Which are knights and which are knaves?
 
Post a new topic to the Traffic Jam Applet tool Discussion discussion  