| Discussion: | Traffic Jam Applet tool |
| Topic: | help quick |
| Related Item: | http://mathforum.org/mathtools/tool/10/ |
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| Subject: | RE: help quick |
| Author: | Eric Goolish |
| Date: | May 2 2004 |
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side of the quadrilateral by using pythagorean's theorem. For instance, the
segment created by points (4,2) and (2,-6), call it A, can be the hypotenus of
a triangle with height 8 and base 2. Then the length of A is just sqrt(8^2 +
2^2). If you do this for all four segments (sides of quad), then sum the
lengths and you will get the perimeter. For my sides I got, sqrt(2^2 + 8^2),
sqrt(7^2 + 2^2), sqrt(5^2 + 9^2), sqrt(1^2 + 10^2). Add them up, and you should
be good to go!
I forgot the distance formula, so that is why I did it this way, but I think
this is the same as the distance formula anyways. If you draw it out using my
method, you should have the quadrilateral lying inside of a rectangle, with the
quadrilateral touching the rectangle at the 4 points you provided.
Sorry it's lengthy and wordy, hope it helps. I hope it's correct too, barring
any arithmetic errors. :)
Eric
If you want further help, just post again and i'll try and clear up any
confusion.
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