| Discussion: | Calculus Made Easy App tool |
| Topic: | Try to solve this. |
| Related Item: | http://mathforum.org/mathtools/tool/3522/ |
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| Subject: | RE: Try to solve this. |
| Author: | Hareen |
| Date: | Aug 21 2004 |
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Yes it sure was easy.
See if u can do this, I wasn't able to do it:
Prove:(n^2)!/(n!)^n is an integer. As a matter of fact this had appeared in one
of the IIT's exam.
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