Discussion:  All Topics in Algebra on Computer 
Topic:  An interesting math puzzle 
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Subject:  An interesting math puzzle 
Author:  Teng 
Date:  Apr 25 2011 
(a~i) each represents a onedigit number(1~9),
and each alphabet mutually different from others
please solve the following interesting puzzle
(c/ab) +(f/de) +(i/gh) =1
Here it is my solution:
1=(1/2)+(1/2)(1)
=(2/3)+(1/3)(2)
=(3/4)+(1/4)(3)
Using (3) we get
1=(3/4)+(1/4)=(9/12)+(17/68)
=(9/12)+(10+7)/68
=(9/12)+(5/34)+(7/68)
I have designed a program to testify this is the only solution
If anyone have found another solution please tell me
Albert.Teng from Taiwan
 
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