![]() |
Teacher2Teacher |
Q&A #104 |

T2T || FAQ || Ask T2T || Teachers' Lounge || Browse || Search || Thanks || About T2T

|
View entire discussion [<< prev] [ next >>]
From: M.J.Bell <mjbell@tenet.edu> To: Teacher2Teacher Public Discussion Date: 1998062714:26:12 Subject: Re: ax^3+ bx^2 y + cxy^2 + dy^3 works great with a factor table. I explained the basic factor table in another message on the public discussion. Here is a specific example such as you asked for. The basic rules of the table are multiply across and multiply down. The numbers in parentheses indicate the order the box is filled in. Factor: 2x^3 - 3x^2y + 4xy^2 - 6y^3 (6) (7) (3) x^2 -3y -3x^2y (8) (9) (4) 2x 2y^2 4xy^2 (1) (2) (5) 2x^3 -6y^3 -12x^3y^3 The factors are (box6 + box 9) (box 8 + box 7) or (x^2 + 2y^2)(2x - 3y) Box 5 is the checking box. If it is not the product down and across, then it will not factor into 2 binomials. Box 6 is the GCF of box 3 and 1. Box 1 always contains the first term and box 2 the last. The two middle terms are interchangeable in boxes 3 and 4.
Post a reply to this message
|
[Privacy Policy] [Terms of Use]

Math Forum Home ||
The Math Library ||
Quick Reference ||
Math Forum Search

The Math Forum is a research and educational enterprise of the Drexel University School of Education.