Q&A #105

Teachers' Lounge Discussion: Math 'to the power of'

T2T || FAQ || Teachers' Lounge || Browse || Search || T2T Associates || About T2T

View entire discussion
[<< prev]

From: Loyd

To: Teacher2Teacher Public Discussion
Date: 2006021714:05:52
Subject: Re: exponents

2^8 can be calculated by: 2x2x2x2x2x2x2x2=4x4x4x4=16x16=256

Post a reply to this message
Post a related public discussion message
Ask Teacher2Teacher a new question

[Privacy Policy] [Terms of Use]

Math Forum Home || The Math Library || Quick Reference || Math Forum Search

Teacher2Teacher - T2T ®
© 1994- The Math Forum at NCTM. All rights reserved.