Q&A #1493

Teachers' Lounge Discussion: Dividing fractions

T2T || FAQ || Ask T2T || Teachers' Lounge || Browse || Search || T2T Associates || About T2T

View entire discussion
[<< prev] [ next >>]

From: Pat Ballew

To: Teacher2Teacher Public Discussion
Date: 2000060308:56:51
Subject: Dividing Fractions

Disclaimer:  I am not an elementary teacher, and my views of teaching
elementary math are formed from working with some very good elementary
teachers at times, both in the US and Japan, and the responses of
students in a few classrooms where I have taught demonstration
lessons.  All in all a very limited experience.  That being clear, I
would still like to offer a comment here.

It seems that dividing a fraction by a fraction is made more difficult
by american teachers and students because they almost always perceive
division as a partitioning process (how many of those in this) rather
than a missing product model (what must that be multiplied by to get
this).  It seems when I talk to teachers in the Orient they are much
more likely to look at both models for examples.  When trying to
explain the "flip and multiply" algorithm, it seems that the missing
product model is much more direct.  
   If that is not clear, an example will perhaps help.

 The division of 3/4 by 1/2 can be written as a missing product
equation 1/2 * ? = 3/4  .  If students are good at multiplying
fractions, they will, I would think, be much less likely to get a
really bad answer for this (I think 3/8 is the most common wrong
answer by students struggling to understand division by fractions,
when students freqently multiply by 1/2 instead of dividing).  It may
be that no algorithm other than guess and test is really necessary for
this... Imagine the most difficult case, all prime values for
numerators and denominators of both cases...
   (2/3)  /  (5/7)   First it is rewritten as a missing product 

  5       ?           2
 ---  * -----   =  -----
  7       ?           3

 I would think any student who has learned to pre-cancel (I'm not sure
what word is in vogue for this process in elementary schools today, so
forgive me if the language is, at times, arcane) then she should see
  We need a 7 in the numerator to get rid of the other 7, and a 2 to
create a 2 in the product, so the quotient must have 14 in the
and... we need a 5 in the denominator to get rid of the other five and
a 3 to make a three in the product, so we need 15 in the denominator, 
giving us a quotient of 14/15.  


Post a reply to this message
Post a related public discussion message
Ask Teacher2Teacher a new question

[Privacy Policy] [Terms of Use]

Math Forum Home || The Math Library || Quick Reference || Math Forum Search

Teacher2Teacher - T2T ®
© 1994- The Math Forum at NCTM. All rights reserved.