Teacher2Teacher 
Q&A #1576 
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From: Tasha To: Teacher2Teacher Public Discussion Date: 2006071909:13:14 Subject: Re: Gradient on curves Yeap... If y=x^3 (X^3 means x cubed) Then firstly you need to draw a graph. Include a point on the x axis that is called x+(delta x) and on the y axis add a point called (x^3+deltax)^3 Then work out the y coordinate which is x^3+3x^2(delta x)+3x(delta x)^2+(delta x)^3 then work out the step: 3x^2(delta x)+3x(delta x)^2+(delta x)^3 divide it by the rise: (delta x) and the gradient is 3x^2 the general rule when y=x^n that the gradient is Nx^n1
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