Teacher2Teacher |
Q&A #1576 |
From: Tasha
To: Teacher2Teacher Public Discussion
Date: 2006071908:13:14
Subject: Re: Gradient on curves
Yeap... If y=x^3 (X^3 means x cubed) Then firstly you need to draw a graph. Include a point on the x axis that is called x+(delta x) and on the y axis add a point called (x^3+deltax)^3 Then work out the y co-ordinate which is x^3+3x^2(delta x)+3x(delta x)^2+(delta x)^3 then work out the step: 3x^2(delta x)+3x(delta x)^2+(delta x)^3 divide it by the rise: (delta x) and the gradient is 3x^2 the general rule when y=x^n that the gradient is Nx^n-1
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