Q&A #1576

Teachers' Lounge Discussion: Graph sketching

T2T || FAQ || Teachers' Lounge || Browse || Search || T2T Associates || About T2T

View entire discussion
[<< prev] [ next >>]

From: Tasha

To: Teacher2Teacher Public Discussion
Date: 2006071909:13:14
Subject: Re: Gradient on curves

Yeap... If y=x^3 (X^3 means x cubed) Then firstly you need to draw a graph. Include a point on the x axis that is called x+(delta x) and on the y axis add a point called (x^3+deltax)^3 Then work out the y co-ordinate which is x^3+3x^2(delta x)+3x(delta x)^2+(delta x)^3 then work out the step: 3x^2(delta x)+3x(delta x)^2+(delta x)^3 divide it by the rise: (delta x) and the gradient is 3x^2 the general rule when y=x^n that the gradient is Nx^n-1

Post a reply to this message
Post a related public discussion message
Ask Teacher2Teacher a new question

[Privacy Policy] [Terms of Use]

Math Forum Home || The Math Library || Quick Reference || Math Forum Search

Teacher2Teacher - T2T ®
© 1994- The Math Forum at NCTM. All rights reserved.