Q&A #193

Teachers' Lounge Discussion: Trigonometry Ratios

T2T || FAQ || Teachers' Lounge || Browse || Search || T2T Associates || About T2T

View entire discussion
[<< prev] [ next >>]

From: Keith Urquhart

To: Teacher2Teacher Public Discussion
Date: 2001050619:32:53
Subject: Re: How do I calculate the three angles in a right triangle?

1.name the three sides of your right-angled triangle: hypotenuse,opposite and adjacent. Hypotenuse being the longest side (opposite the right angle) Opposite being opposite the angle you are trying to find. 2. Using any one of the ideas that other people have used here... I use Soh Cah Toa Sin= o/h Cos= a/h Tan= o/a In your example, lets say the shorter sides are 4 and 5 for example... you would use the opposite and adjacent sides (as you have that information: therefore Tan= o/a which in this case could be Tan= 4/5 Then using your scientific calculator, or log tables, calculate the measure of your angle. best wishes, ps we don't say math, but maths (short for mathematics) Keith (teacher in the UK)

Post a reply to this message
Post a related public discussion message
Ask Teacher2Teacher a new question

[Privacy Policy] [Terms of Use]

Math Forum Home || The Math Library || Quick Reference || Math Forum Search

Teacher2Teacher - T2T ®
© 1994- The Math Forum at NCTM. All rights reserved.