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From: Michael Sakowski To: Teacher2Teacher Public Discussion Date: 2007082708:29:24 Subject: Calculus Project - Newton's Law of Cooling Here's a nice hands-on project for your students that I wrote up. COFFEE TIME IS CALCULUS TIME Introduction: In this project you will compare how well your favorite coffee cup keeps a hot cup of coffee hot. You will solve a differential equation for the temperature in the cup and use this to predict how long it will take for the coffee to get cold in the cup. According to newtons law of cooling and heating, the rate of cooling of an object is directly proportional to the difference of the temperature of the object and medium surrounding the object. This is given by the equation dy/dt = k(y - M) where dy/dt = rate of change of temperature of the substance, M = the temperature of the surrounding medium, y = the temperature of the substance at any given time t, and k = a constant that must be solved for. Procedure 1.Record the room temperature. This is the temperature M from the above equation. 2.Find a coffee cup that you wish to test. Fill the cup with hot tap water (or coffee). 3.Place the thermometer into the cup. After a minute or two, record the temperature in the cup and record the time. Use a stopwatch if you have one. This is the initial temperature yo. (Time is t = 0) 4.Just before 6 minutes, stir the cup with the thermometer. Then measure the temperature of the cup at exactly 6 minutes. 5.Just before 20 minutes, stir the cup with the thermometer. Then measure the temperature of the cup at exactly 20 minutes. ROOM TEMPERATURE = _______ TIME TEMPERATURE INITIAL TIME ______ (t = 0) 6 MINUTES ______ 20 MINUTES ______ WRITE-UP QUESTIONS ARE ON THE FOLLOWING PAGE Write-up 1.Solve the separable equation dy/dt = k(y - M) and obtain a general solution. 2.Use the data at time t=0 and t=6 to find the particular solution for this experiment.(Solve for k and C. M = room temp) 3.Compute the temperatures at time t=20 by using your particular solution that you just found. 4.Compute the percent difference between the measured temperature and computed temperature at t=20 minutes. This is (measured - computed)/measured X 100% 5.Explain why the measured temperature was higher than the computed temperature. 6.Using the particular solution, predict the time it will take for the temperature in the cup to be 1 degree higher than the room temperature. 7.Discuss ways in which your coffee cup could be made more efficient in holding in heat.
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