![]() |
Teacher2Teacher |
Q&A #5978 |

T2T || FAQ || Ask T2T || Teachers' Lounge || Browse || Search || Thanks || About T2T

|
View entire discussion [<< prev] [ next >>]
From: Loyd <loydlin@aol.com> To: Teacher2Teacher Public Discussion Date: 2003032310:18:24 Subject: Re: how do I figure out prime factorization? On 2003032307:23:21, Nyla wrote: > >Please help me figure out the prime factorization for a number like >1713.I have trouble with big numbers. > To start, you only have to search for prime numbers less than the square root of 1713. These prime numbers are: 2,3,5,7,11,13,17,19,23,29,31,37,41. That looks like a hard problem but usually it is easy. Since the number is odd, we can eliminate 2. We next use the sum of the digits test for 9 and 3. 9 is not prime, but since the test is easy, I always use it if the sum of the digits add to a number divisible by 9. The sum of the digits is 12, so 3 is a factor but 9 is not. 571 x 3 and we then only have to search up to 23 because the truncated square root of 571 = 23. Five won't work by inspection so, what I do is get the handy calculator and try dividing by 7,11,13,17,19,23. Only takes a moment. You find that 571 is prime. So, the factors of 1713 = 3 x571. I checked my answer with my 149 dollar TT-89 calculator which has a factor function. This calculator is not required in many college math courses but usually not in high school. Many text books have divisibility rules for 2, 3, 4, 5, 6, 8, 9 and 11. It helps to learn these.
Post a reply to this message
|
[Privacy Policy] [Terms of Use]

Math Forum Home ||
The Math Library ||
Quick Reference ||
Math Forum Search

The Math Forum is a research and educational enterprise of the Drexel University School of Education.