Teacher2Teacher 
Q&A #9409 
View entire discussion [<< prev] [ next >>]
From: Joan <witefairy75@yaoo.com> To: Teacher2Teacher Public Discussion Date: 2005031720:23:29 Subject: Re: Re: Re: Simplifying Try multiplyin 6(14b) When we consider 624b, we look at it as: (6x1)(6x4b) Thus when we take the common factor 6 out we will get 6(14b). Hope this one did help clearing your doubt. Once again since the numerator is 4b1, we take 6 out from the denominator so that we get 6(4b1). Hope it is clear for you now.
Post a reply to this message

[Privacy Policy] [Terms of Use]
Math Forum Home 
The Math Library 
Quick Reference 
Math Forum Search