Teacher2Teacher 
Q&A #9409 
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From: Joan To: Teacher2Teacher Public Discussion Date: 2005031721:23:29 Subject: Re: Re: Re: Simplifying Try multiplyin 6(14b) When we consider 624b, we look at it as: (6x1)(6x4b) Thus when we take the common factor 6 out we will get 6(14b). Hope this one did help clearing your doubt. Once again since the numerator is 4b1, we take 6 out from the denominator so that we get 6(4b1). Hope it is clear for you now.
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