Q&A #19440


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From: Gail (for Teacher2Teacher Service)
Date: Mar 30, 2008 at 08:30:02
Subject: Re: Combinations

Hi Sandra,

Let's try an easier problem first. How many committees consisting of 1 person
can be formed from 3 people? Just 3, right? If the people are a, b, and c,
you can have a, b, or c as committees.

What about forming two-person committees? Then you could have ab, ac, ba,
bc, ca or cb as committees, right?  That is 6 committees. But wait a
minute…  wouldn’t the committee of ab be the same as the committee of ba?
So you started with 6 options, but discarded 3 of them, and really you only
have ab, ac, or bc, three committees.

Let’s try it again, but this time, let’s use four people: a, b, c, and d.

Two person committees:  ab, ac, ad, bc, bd, cd (we discarded ba, ca, cb, da,
db, and dc). So you started with 12 options, and threw out 6 of them.

Here is a picture of what is happening:

AB   ba   ca   da
AC   BC   cb   db
AD   BD   CD   dc

The ones we are using are in capital letters, and the ones that are
duplicated are lower case.

Now, what about three person committees? If you start with three people, a,
b, and c, there is only one committee, abc.

If you have four people to start with (a, b, c and d), the committees might
be abc, abd, or acd or bcd.  All of the other combinations would be
duplicates of the ones listed.

Here is a picture of what is happening:

ABC     bac     cab     dab
ABD     bad     cad     dac
acb     bca     cba     dba
ACD     BCD     cbd     dbc
adb     bda     cda     dca
adc     bdc     cdb     dcv

What if you start with 5 people in your group (a, b, c, d and e), and want
to choose 3-person committee?  abc, abd, abe, acd, ace, ade, bcd, bce, bde,
and cde are left if you discard all the duplicates.

I found the following sites that could also be of help:



I hope this is helpful.

 -Gail, for the T2T service

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