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Hi Dana, One strategy is to make a systematic list of all possibilities and to pretend you are working with two different colored number cubes. I'll pretend I have a red number cube and a yellow number cube. I'll record them as ordered pairs: (R, Y). (1,1); (1,2); (1,3); (1,4); (1,5); (1,6) (2,1): (2,2); ... Assuming that you are systematic in your thinking and recording, you'll find a total of 36 possible outcomes. Of the 36, 11 outcomes have at least one 6. Cheers! -Jeanne, for the T2T service
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