![]() |
Teacher2Teacher |
Q&A #3398 |

T2T || FAQ || Ask T2T || Teachers' Lounge || Browse || Search || Thanks || About T2T

|
View entire discussion [<<prev]
I can't think of a "catchy" way, but basically, permutations deal with
arrangements. I usually have my students draw little lines to represent how
many things I am arranging. For example, if the problem says how many ways
can a family of five be seated in a row for a picture? I have my students
make five blanks ___ ___ ___ ___ ___
Then I go blank by blank and ask how many choices do I have...for the first
blank? 5
Second blank....since people can't be repeated there are 4 choices left
then 3
then 2
then 1
so the answer is 5 X 4 X 3 X 2 X 1 = 120 ways
Now suppose my mom and dad had to sit on the ends???
___ ___ ___ ___ ___
the first seat now only has 2 choices (mom or dad)
the second seat has only 3 choices (one of the kids)
work down...it looks like
2 X 3 X 2 X 1 X 1 = 12 ways (the last seat is a one because if
mom or dad sat in the first seat, it leaves only one person left)
Hope this helps
-Claudia, for the Teacher2Teacher service
Post a public
discussion message |
[Privacy Policy] [Terms of Use]

Math Forum Home ||
The Math Library ||
Quick Reference ||
Math Forum Search

The Math Forum is a research and educational enterprise of the Drexel University School of Education.