Hosted by The Math Forum

Problem of the Week 1090

A Painted Cube

_____________________________________________
MacPOW Home || Math Forum POWs || Search MacPOW
_____________________________________________

Solution

The problem leads to finding to roots for the equation ...

6(n - 2)2 = (n - 2)3

... and there are two distinct roots: 2 and 8. A proper solution *must* address both of these roots and either accept the trivial n = 2 as a reasonable solution or reject it. In my opinion, you can make a reasonable case either way about n = 2. I leave it to you to decide where you fall.

In short, a solution that directly addresses the n = 2 case is more complete.

In response to the solution, some people suggested that if n = 2 is legitimate then n = 1 (there are no cuts) and n = 0 (there is no cube) should be solutions, as well. If you decide that you accept the trivial n = 2 solution, then you also get to decide whether you like these solutions. I prefer to interpret the problem as (1) the cube does exist and (2) Alice did cut it.

[Back to Problem 1090]

© Copyright 2008 Stan Wagon. Reproduced with permission.

[Privacy Policy] [Terms of Use]

_____________________________________
Home || The Math Library || Quick Reference || Search || Help 
_____________________________________

© 1994-2008 Drexel University. All rights reserved.
http://mathforum.org/
The Math Forum is a research and educational enterprise of the Drexel School of Education.The Math Forum is a research and educational enterprise of the Drexel School of Education.


21 February 2008