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Heron's Method for Finding Square Roots by HandDate: 12/18/2001 at 03:06:54 From: Alvin Folks Subject: Square Root How do you get the square root of a number manually without a table or calculator? Example: sqrt.root of 62, 588, and 46. Take the sqrt. root of 58; the answer is 7.6157. I got the 7 and the decimal point. I do not know how you get the 6 and 1, etc. Thank you, Rolleralvin
Date: 12/18/2001 at 08:46:59
From: Doctor Paul
Subject: Re: Square Root
I suppose the easiest way to do this is to guess and check. For
example, to compute sqrt(62):
You know the answer is somewhere between 7 and 8 (closer to 8) so we
guess that the answer is 7.8
Now square 7.8 and see if 7.8 is too big or too small.
7.8^2 = 60.84
so 7.8 is too small.
Try 7.9
7.9^2 = 62.41
so 7.9 is too big.
Try 7.88
7.88^2 = 60.0944
so 7.88 is too big
try 7.87
7.87^2 = 61.9369
so 7.87 is too small.
Try 7.874.
7.874^2 = 61.999876
which is very close to 62.
But of course it's not sqrt(62) so we can repeat the above process
basically forever if we so desire.
Now, using a calculator, I compute:
sqrt(62) = 7.874007874011811019685034448...
This verifies that the above method was indeed leading us in the right
direction.
A much better method was known to Heron (of Alexandria), who is
believed to have lived between 150 BC and 250 AD. He noted that if you
pick a_1 as a random guess for a possible value of sqrt(n) then
a_2 = [a_1 + (n/a_1)]/2
will be a better approximation.
Similarly,
a_3 = [a_2 + (n/a_2)]/2
will be a better approximation than a_2.
These approximations form a sequence of numbers {a_i} that converge
very rapidly to sqrt(n). For example:
If we desire to compute sqrt(62) and we take a_1 = 7
we compute:
a_2 = [7 + (62/7)]/2 = 111/14 = 7.928571428571428571428571428...
then
a_3 = [111/14 + (62/(111/14))]/2 = 24473/3108 =
7.874195624195624195624195624...
continuing, we obtain:
a_4 = 1197826897/152124168 = 7.874007876250143238252583244
which is accurate to eight decimal places.
As before, we can continue the process indefinitely if we want.
I hope this helps. Please write back if you'd like to talk about this
some more.
- Doctor Paul, The Math Forum
http://mathforum.org/dr.math/
Date: 12/19/2001 at 23:30:27
From: Alvin Folks
Subject: Square Root
I would like to thank you Doctor Paul for your help and speedy reply
It more than satisfied my understanding of finding the square root of
a number by hand.
Thank you,
Rolleralvin2
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