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Topic: The non existence of p'th root of any prime number, for (p>2)
prime

Replies: 46   Last Post: Oct 12, 2017 1:41 AM

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 zelos.malum@gmail.com Posts: 405 Registered: 9/18/17
Re: The non existence of p'th root of any prime number, for (p>2) prime
Posted: Oct 5, 2017 6:24 AM

Den torsdag 5 oktober 2017 kl. 11:43:09 UTC+2 skrev bassam king karzeddin:
> On Thursday, October 5, 2017 at 12:01:42 PM UTC+3, Zelos Malum wrote:
> > Den söndag 19 februari 2017 kl. 18:30:04 UTC+1 skrev bassam king karzeddin:
> > > Why does the trustiness of Fermat's last theorem implies directly the non existence of the real positive arithmetical p'th root of any prime number
> > > ($\sqrt[p]{q}$)?
> > >
> > > Where (p) is odd prime number, and (q) is prime number
> > >
> > > It is an easy task for school students NOW!
> > >
> > > Regards
> > > Bassam King Karzeddin
> > > 19/02/17

> >
> > It is trivial to show that they do exist, considering it is trivial to use newton-raphner method to create a cauchy sequence that converges to it.

>
> Newton-raphner! Cauchy sequences! Deadkin's cuts! Origami! Paper folding. ....etc, wouldn't create you any of my alleged fiction angles in any imaginable universe
> Because the ignorance in perfect mathematics is well established globally and beyond any limit for more than sure
>
> But I know how does it work fictionally in those little skulls
>
> BKK

Just because you do not understand those things doesn't mean it doesn't work. And actually using all those we can create it all, again it is extremely simple.

> which damn logic is that? wonder!

The one and only.

Take the set of cauchy sequences of rational numbers modulo null sequences and you got real numbers, which includes all of the roots you spoke off. It is an easy construct.

Take the dedekind-macneille completion of rational numbers, same thing there. Here we can construct the lower cut by having p^n<q to get the n'th root of q.