Ed Wall
Posts:
837
Registered:
12/3/04
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Re: Height of a Triangle
Posted:
May 7, 2002 11:10 AM
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Actually, I was thinking of what Steve referred to and which is
essentially Mary's second expression below. This seems better than
mucking around with angles, but still feels somehow like it is too
much.
Ed Wall
>Did Ed Wall give you his "messy" method? I did not see it. I suppose
>that finding an angle and using it, as you suggest you can, is less
>messy.
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>Standard formulas for an angle, given three sides, are:
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>cos A = (b^2 + c^2 - a^2)/(2*b*c)
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>sin A = 2*sqrt(s(s-a)(s-b)(s-c)/(b*c)
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>A is the angle opposite side a. s = (a+b+c)/2.
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>Mary Krimmel
>mary@krimmel.net
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>At 03:07 PM 5/6/02 -0400, you wrote:
>>I have been out of high school for about 8 years now, so I forget most
>>of my simple geometry. I have a triangle (of which I know the length
>>of all sides). I need to find the height of the triangle (the
>>perpendicular distance from one of the sides to the opposing corner).
>>I could do it with simple trig if I knew one of the angles. I assume
>>that I can figure out all of the angles given all three sides, I just
>>don't remember how to calculate these. This triangle is not a right
>>triangle.
>>
>>Post here to respond. Thanks in advance.
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