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Re: feet of altitudes and angles
Posted:
Nov 27, 1997 9:12 PM


> Prove that the angles formed by connecting the feet of the > altitudes of a > triangle are themselves bisected by the altitudes.
In fact, you don't need 3 altitudes  one is enough.
In an acute triangle ABC, let M be the point on BC such that AM is an altitude. Let P be any point on AM, let BP meet AC at Q, and let CP meet AB at R. Then AM bisects angle QMR, even if BQ and CR are not altitudes.  Barry Wolk  Did you know that the word "pizza" Dept of Mathematics  is a mathematical formula? It is University of Manitoba  the volume of a circular pizza of Winnipeg Manitoba Canada  radius "z" and thickness "a".



