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Re: not A=(1/2)bh
Posted:
Jul 24, 1998 10:40 AM


Yes, you can derive Heron's Formula for by choosing a vertex, dropping a perpendicular, and eliminating variables. The funny thing is that Heron's Formula is symmetrical in the variables a,b, and c....so why do you have to use a proof that's so UNsymmetrical?
It's a good problem to look for a symmetrical derivation of Heron's Formula...one that doesn't start by choosing a particular side as the "base". I know of two such methods.
Marty



