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Re: Composites, and neat relation
Posted:
Sep 13, 2004 6:06 PM


Paul Murray <paul@murray.net> wrote in message news:<fnc1d.1286704$y4.226290@news.easynews.com>... > In article <3c65f87.0409121727.2ef5c7a8@posting.google.com>, James Harris wrote: > > jstevh@msn.com (James Harris) wrote in message news:<3c65f87.0409121043.5988edb8@posting.google.com>... > >> So someone pointed out that there's the trivial relation > >> > >> [x] + [x + 1/2] = [2x] where you're in reals, > >> > >> and I started thinking about > >> > >> [x] + [x + 1/k] = [2x] > >> > >> also in reals, with k>1, and it turns out you need x>1 as well, which > >> I was thinking about didn't put down before. > > > > You can have x less than 1 as what's needed is > > > > xk + 1 >= k > > Still false.
You're right. The requirement is that x>=1.
James Harris



