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Topic: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Replies: 36   Last Post: Jan 20, 2007 7:43 AM

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Leonard M. Wapner

Posts: 58
Registered: 12/13/04
Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Posted: Jan 1, 2007 10:26 AM
  Click to see the message monospaced in plain text Plain Text   Click to reply to this topic Reply

Bounded? Convergent?

Calculating the first 100 terms (Mathematica) suggests convergence. If I go
up to 500 terms, it appears to converge.

Other than a heuristic investigation, can problems of this sort
(indeterminate nature) be done formally?

Happy New Year!

LW






Date Subject Author
1/1/07
Read Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Leonard M. Wapner
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
David W. Cantrell
1/12/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Gerry Myerson
1/12/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
David W. Cantrell
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
James Waldby
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
James Waldby
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Dana DeLouis
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/2/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/1/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Leonard M. Wapner
1/2/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Jules
1/2/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
David W. Cantrell
1/2/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
David Bernier
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
David Bernier
1/2/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Michael Press
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
David W. Cantrell
1/2/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
James Waldby
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/4/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
James Waldby
1/4/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/4/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/6/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
Michael Press
1/6/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/4/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
David Bernier
1/4/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
David Bernier
1/6/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/7/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
David Bernier
1/7/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
David Bernier
1/7/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin
1)(sin 2)(sin 3) ... (sin n)
James Waldby
1/7/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/3/07
Read Re: Sequence: a(n)=(2 sin 1)(2 sin 2)(2 sin 3)...(2 sin n) = (2^n)(sin 1)(sin 2)(sin 3) ... (sin n)
matt271829-news@yahoo.co.uk
1/20/07
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Leonard M. Wapner

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