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Re: Area problems
Posted:
Jul 7, 2008 10:37 AM


First, the function is nit "sen" but "sin".
Second, sin(45) = sqrt(2)/2 which is only approximately equals 0.707106781.
So, your formula gives:
A = 1/2 (4)(5)(sen 45) = 10 sqrt(2) / 2 = 5 sqrt(2),
as is declared in the book.
A. Bogomolny http://www.cuttheknot.org



