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Topic: Proving trigonometric identities
Replies: 32   Last Post: Jan 27, 2009 1:59 AM

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 Angus Rodgers Posts: 1,683 Registered: 7/16/07
Re: Proving trigonometric identities
Posted: Jan 23, 2009 5:21 AM
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On Fri, 23 Jan 2009 00:41:45 -0800 (PST), Albert
<albert.xtheunknown0@gmail.com> wrote:

>This (I think) is the last trig proof I've to do (there may be some in
>the next booklet though):
>
>(tan x + sec x - 1) / (tan x - sec x + 1) = (1 + sin x) / cos x
>
>I've tried turning the tan and sec into sin and cos but I can't
>factorise the resulting fraction down to a denominator of cos x. Also,
>I've tried rationalising the fraction but it can't be simplified.
>What's a key idea I should consider to tackle this proof?

There may be a neater way to do it, but one fairly short way is
to do the same first step as I suggested for the first problem,
which is to rewrite A/B = C/D as AD = BC. The left hand side
of the latter identity simplifies to 1 + sin x - cos x. Does
the right hand side simplify to the same expression?

--
Angus Rodgers

Date Subject Author
1/20/09 Albert
1/20/09 Angus Rodgers
1/20/09 Albert
1/20/09 Angus Rodgers
1/20/09 Albert
1/20/09 Angus Rodgers
1/20/09 Angus Rodgers
1/20/09 Guest
1/20/09 Angus Rodgers
1/20/09 Albert
1/20/09 Angus Rodgers
1/20/09 matt271829-news@yahoo.co.uk
1/21/09 Albert
1/21/09 adder
1/21/09 matt271829-news@yahoo.co.uk
1/23/09 Albert
1/23/09 Angus Rodgers
1/23/09 Angus Rodgers
1/23/09 Passerby
1/23/09 Dave Dodson
1/24/09 Albert
1/24/09 Angus Rodgers
1/24/09 Albert
1/26/09 Albert
1/26/09 Driveby
1/26/09 Albert
1/26/09 A N Niel
1/27/09 Albert
1/20/09 adder
1/20/09 victor_meldrew_666@yahoo.co.uk
1/20/09 Dave Dodson
1/20/09 Pfsszxt@aol.com
1/20/09 Albert

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