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Topic:
n square free) ^ ( d I n and u = v (mod d) > f(u) = f(v) (mod d) ) > (f is a polynomial over Z_n)
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2
Last Post:
Oct 16, 2009 3:37 PM




Re: n square free) ^ ( d I n and u = v (mod d) > f(u) = f(v) (mod d) ) > (f is a polynomial over Z_n)
Posted:
Oct 16, 2009 3:37 PM


On Oct 16, 10:10 am, Olivier <O...@nowhere.wd> wrote: > G Patel a écrit : > > > How can I show that for any squarefree n and function f from Z_n to > > Z_n that has the propery that whenever d I n and u = v (mod d) then f > > (u) = f(v) (mod d)  must be a polynomial over Z_n ? > > This is true when n is a prime. > Use the chinese remainder Theorem. > A.O.
is there a counterexample for when n is squarefree and not a prime? how about when n is not squarefree?



