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Topic: N^19 + 10N ^19 = XN000000000-XN infinatum-- CASE AGAINST
FERMAT/WILES- PARIS BURNS!

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Re: N^19 + 10N ^19 = XN000000000-XN infinatum-- CASE AGAINST
Posted: Dec 18, 2009 11:22 AM
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ec 18, 6:53 am, "Dik T. Winter" <Dik.Win...@cwi.nl> wrote:
> In article <8d54169c-6372-493e-8ccf-f7f2c6974...@k4g2000yqb.googlegroups.com> Inverse 19 mathematics <hope9...@verizon.net> writes:
>  > 3^19 +30^19 = 1162261467000000000001162261467  those "last and first
> shouldimport java.util.^;A

public class AreaOfSquare {
public static void main (String[]args){
Scanner in = new Scanner(System.in);
int a, s; //declare the 'boxes' to hold side and area
System.out.printf("Enter length of side: ");
s = in.nextInt(); //read and store length in s
a = s * s; //calculate area; store in a
System.out.printf("\nArea of square is %d\n",a);
'Asku' algorithm by MeAmI.org
All Rights Reserved. Copyright 2009.
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}//end class AreaOfSquare be:         11622614670000000001162261467
>  > numbers" like 2^19 stay the same infinatum +10n, stble in
>  > multiplication and deivisions,,, AND this is true for infinite
>  > combinations that are unpredicatable, 4^19, 5^19--- so on , and the
>  > transverse combinations of 19 zeros ---
>
> 3^18 +30^18 = 387420489000000000387420489  those "last and first
> numbers" like 2^18 stay the same infinatum +10n, stble in
> multiplication and deivisions,,, AND this is true for infinite
> combinations that are unpredicatable, 4^18, 5^18--- so on , and the
> transverse combinations of 18 zeros ---
> --
> dik t. winter, cwi, science park 123, 1098 xg amsterdam, nederland, +31205924131
> home: bovenover 215, 1025 jn  amsterdam, nederland;http://www.cwi.nl/~ Results 1 - 10 for .001 EQUALIZE inverse fractionation. (0.25 seconds)


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