
Re: changing variable in an equation
Posted:
Feb 12, 2011 5:20 AM


You have a missing parenthesis, so I'll have to guess where you wanted it.
Your three examples don't seem to match the phrase "working from 100 to 100".
And there's a third variable  x  that you haven't explained. I'll give it a fixed value.
So... working from 10 to t+10 to save time, and t varying from 0 to .1 so that everything isn't obscured by the scale:
Clear[v] v[i_, x_, t_] = 67 + (10 (i  1) + 67) x E^(19 x t)/10; x = 3; Plot[Evaluate@Table[v[i, x, t], {i, 10, 10}], {t, 0, .1}, PlotRange > All]
In case it's x that should vary from 100 to 100, then I don't know what values i should take on.
But... if you want to vary both, here's an example:
Plot[Evaluate@Table[v[i, x, t], {i, 10, 10}, {x, 0, 3}], {t, 0, .1}, PlotRange > All]
Notice that this is colored differently:
Plot[Table[v[i, x, t], {i, 10, 10}, {x, 0, 3}], {t, 0, .1}, PlotRange > All]
That's what Evaluate is about, in the other plots.
Bobby
On Fri, 11 Feb 2011 03:17:10 0600, J and B <noslowski@comcast.net> wrote:
> Below is an equation that I am working on. I know there is some way to > work > it out better than what I am doing. I would like the variable a to > change > in increments of 10, from 100 to 100. > Thanks > my main equation is: v = 67+(a(67) x E ^ (19 x t)/10 > what I am doing: > v1= 67+(0(67) x E ^ (19 x t)/10; > v2= 67+(10(67) x E ^ (19 x t)/10; > v3= 67+(20(67) x E ^ (19 x t)/10; > and so on and working from 100 to 100 > Then I use > Plot [ { v1,v2, v3 ........},{t,0,5}, PlotRange > All] > Please note that I have added some spaces in to make it more readable. > thanks > Jake
 DrMajorBob@yahoo.com

