h.jones
Posts:
32
From:
uk
Registered:
2/21/08


Re: Einstein's factor of 2 in starlight deflection
Posted:
Sep 3, 2011 1:47 PM


On Aug 23, 12:21 pm, "H.Jones" <h.jone...@googlemail.com> wrote: > To obtain g at Planck time we merely divide our current SI G by the > Planck frequency squared which is the same thing as multiplying G by > Planck time squared. (6.6712139x10^11)/ > (3.7007618x10^42)^2=4.87105x10^96. > {(4.87105x10^96)x(2x10^30kg)}/(2.9690906x10^3m)^2=1.1051104x10^72m, > g at one Planck time unit per time unit. > Incidentally, if you take a look at this Planck G, 4.87105x10^96, > divide by the Sun's Compton wavelength, 1.1051104x10^72, you wind up > with the reciprocal of 2.2687315x10^23 which is the frequency of the > Compton wavelength of the proton.
The interesting thing about the Sun/proton mass content of the G/ Planck frequency squared situation is what does it mean and where does it lead to? Central to the basic principle is C/G. C because the area under discussion concerns the kilogram/second and G because we need to find it. All magnitudes of mass have a Schwarzshild diameter and a Compton wavelength. They mirror one another because they are equidistant, differentially, from the Planck length; one is bigger than the Planck length and the other is smaller. In this situation these magnitudes of mass have a twin where the situations are reversed, the Schwarzschild diameter is equal to the other's Compton wavelength and vice versa. The opposite to the kilogram, for instance, is the planck mass squared. The opposite of the mass represented by G/ C is h/4 or 1.65651887x10^34kg, and so on. If we divide 2x10^30kg by 1.672623x10^27kg, the Sun and proton masses, we arrive at 1.1957267x10^57. We can arrive at a fairly accurate assessment of the radius by dividing this figure by (c^2)/h, the frequency of the kilogram's Compton wavelength, which provides us with (2.9690906x10^3m)^2. So. 2.9690906x10^3m can be considered a fairly reliable approximation of the Schwarzschild radius of a mass, 2x10^30kg. Now, the radius of our own kg/second system is, obviously, C/2, therefore, the analogue of 1.1957267x10 ^57 is [(C/2)^2][c^2/ h]=3.047659486x10^66 which is equal to 1.0097113x10^35kg, the current approximation of the kilogram/second timescale mass, divided by 3.313071538x10^32kg, which is, in this context, the analogue of the proton mass. If we travel on a little further, somewhat higher than our own kilogram/second time scale mass, until we reach an analogue to the proton mass of h/4, 1.65651887x10^34kg, we get a timescale mass of 2x1.009721668x10^37kg. This is represented by the ratio 1.672623x10^27, the proton mass, over h/4, which equals 1.00972167x10^7. Multiply this by the Sun's mass and we arrive at the figure above. We know that the proton's Compton wavelength is 1.32141x10^15m. We know that (C/2)/2.9690906x10^3m=5.048556x10^4. 1.32141x10^15x5.048556x10^4=6.6712139x10^11, or G. Or else, the Compton wavelength of the proton's kilogram/second time scale's mass analogue, 3.31307153x10^32kg, is also equal to G or 6.6712139x10^11.

