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Topic: Einstein's factor of 2 in starlight deflection
Replies: 10   Last Post: Dec 3, 2012 5:05 PM

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h.jones

Posts: 32
From: uk
Registered: 2/21/08
Re: Einstein's factor of 2 in starlight deflection
Posted: Sep 3, 2011 1:47 PM
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On Aug 23, 12:21 pm, "H.Jones" <h.jone...@googlemail.com> wrote:
> To obtain g at Planck time we merely divide our current SI G by the
> Planck frequency squared which is the same thing as multiplying G by
> Planck time squared. (6.6712139x10^-11)/
> (3.7007618x10^42)^2=4.87105x10^-96.
> {(4.87105x10^-96)x(2x10^30kg)}/(2.9690906x10^3m)^2=1.1051104x10^-72m,
> g at one Planck time unit per time unit.
> Incidentally, if you take a look at this Planck G, 4.87105x10^-96,
> divide by the Sun's Compton wavelength, 1.1051104x10^-72, you wind up
> with the reciprocal of 2.2687315x10^23 which is the frequency of the
> Compton wavelength of the proton.


The interesting thing about the Sun/proton mass content of the G/
Planck frequency squared situation is what does it mean and where does
it lead to? Central to the basic principle is C/G. C because the
area under discussion concerns the kilogram/second and G because we
need to find it. All magnitudes of mass have a Schwarzshild diameter
and a Compton wavelength. They mirror one another because they are
equi-distant, differentially, from the Planck length; one is bigger
than the Planck length and the other is smaller. In this situation
these magnitudes of mass have a twin where the situations are
reversed, the Schwarzschild diameter is equal to the other's Compton
wavelength and vice versa. The opposite to the kilogram, for instance,
is the planck mass squared. The opposite of the mass represented by G/
C is h/4 or 1.65651887x10^-34kg, and so on. If we divide 2x10^30kg by
1.672623x10^-27kg, the Sun and proton masses, we arrive at
1.1957267x10^57. We can arrive at a fairly accurate assessment of the
radius by dividing this figure by (c^2)/h, the frequency of the
kilogram's Compton wavelength, which provides us with
(2.9690906x10^3m)^2. So. 2.9690906x10^3m can be considered a fairly
reliable approximation of the Schwarzschild radius of a mass,
2x10^30kg. Now, the radius of our own kg/second system is, obviously,
C/2, therefore, the analogue of 1.1957267x10 ^57 is [(C/2)^2][c^2/
h]=3.047659486x10^66 which is equal to 1.0097113x10^35kg, the current
approximation of the kilogram/second timescale mass, divided by
3.313071538x10^-32kg, which is, in this context, the analogue of the
proton mass. If we travel on a little further, somewhat higher than
our own kilogram/second time scale mass, until we reach an analogue to
the proton mass of h/4, 1.65651887x10^-34kg, we get a timescale mass
of 2x1.009721668x10^37kg. This is represented by the ratio
1.672623x10^-27, the proton mass, over h/4, which equals
1.00972167x10^7. Multiply this by the Sun's mass and we arrive at the
figure above.
We know that the proton's Compton wavelength is 1.32141x10^-15m. We
know that (C/2)/2.9690906x10^3m=5.048556x10^4.
1.32141x10^-15x5.048556x10^4=6.6712139x10^-11, or G. Or else, the
Compton wavelength of the proton's kilogram/second time scale's mass
analogue, 3.31307153x10^-32kg, is also equal to G or 6.6712139x10^-11.



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