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Ben Brink
Posts:
201
From:
Rosenberg, TX
Registered:
11/11/06


RE: math question  need help
Posted:
Oct 21, 2011 8:22 PM



Dave, When x = y, the conditions imply that k = x and k = 2y. Therefore 2y = y, so x = y = 0. For x > y, I'm getting x = [5 +/ sqrt(593)]/2, so do we get two intervals for y? In general x = [11 +/ sqrt(289 + 6k)]/2. If x < y we can replace k by 2y and solve for y in terms of x. I can't see what we do with that either. Thanks and will be waiting for what others find. Ben
> Date: Fri, 21 Oct 2011 09:31:11 0400 > From: discussions@mathforum.org > To: discretemath@mathforum.org > Subject: math question  need help > > I received this question and I have no clue how to go about answering it. Any help or guidance would be appreciated. there is a + sign with a circle around it, never been taught that before. > > x + (with cirlce around it) y = (x +7)(x + 4)  6k. If x is greater than or equal to y, then k = x. If x is less than or equal to y, then k = 2y. If x + (with cirlce around it) y = 170, find all distinct possible values of y. > > I don't even know where to begin.



