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Topic: Einstein's factor of 2 in starlight deflection
Replies: 12   Last Post: Jul 14, 2014 3:17 PM

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 h.jones Posts: 32 From: uk Registered: 2/21/08
Re: Einstein's factor of 2 in starlight deflection
Posted: Oct 27, 2011 9:24 AM
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The subject matter here has digressed somewhat from title's subject, the bending of starlight under the Sun's gravitational pull. It rather evolved that way and as we are still dealing with the Sun one could claim a link of sorts.

The interesting thing about this derivative of the proton, the symmetrical proton monitor, 6.07142x10^-27kg and the Sun's new master mass, 5.5098x10^29kg, is how much further unity is made. The differential, 3.629879, is made from the difference between the proton mass and h/4, which equals 1.009721667x10^7.
Multiply this by the Planck mass and the reciprocal is 3.629879. But all magnitudes of mass have Compton/Schwarzschild opposites. An opposite's Compton wavelength is equal to the Schwarzschild diameter of the current mass. The Compton wavelength of 6.07142x10^-27kg is 3.64036876x10^-16m, divide this into 4and you have 1.0987898x10^16m, c/Planck mass. We can also find the GM product of the opposite. If the Schwarzschild diameter was 3.64x10^-16m, as above, then its GM product must be 8.1795011. Call this x for the moment and consider the following:
x/c=Planck mass.
(x^2)/h=1.0097114x10^35kg, the kilogram/second timescale mass.
h/x=Planck length and halve this for Planck radius.
And, c(m^2)/G is equal to 2x1.672623x10^3. Divide by the proton mass and you have 2x10^30. There are many leaves to turn.

Date Subject Author
8/20/11 h.jones
8/20/11 h.jones
8/24/11 h.jones
9/3/11 h.jones
9/10/11 DotProduct Quantum
10/9/11 h.jones
10/27/11 h.jones
1/7/12 h.jones
8/22/12 haroldj.l.jones@gmail.com
12/3/12 haroldj.l.jones@gmail.com
7/12/14 haroldj.l.jones@gmail.com
7/14/14 haroldj.l.jones@gmail.com

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