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Topic: new functional operator
Replies: 27   Last Post: Jun 3, 2012 5:05 AM

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Murray Eisenberg

Posts: 2,097
Registered: 12/6/04
Re: new functional operator
Posted: Mar 10, 2012 6:21 AM
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An unfortunate choice of notation, \[Del], for that operator. After all
\[Del] is a universal notation for grad, the gradient operator.

On 3/9/12 6:09 AM, roby wrote:
> Ok, next version.
>
> One can look for an prefix operator with no buit in meaning to modify
> the function in question such that it acts mapping,
> this way we can use the standard // postfix operator and just modify
> the behavoir of the function:
>
>
> \[Del] fn_ := fn /@ #&
>
> {1,2,3,4}//\[Del]f//\[Del]g
>
> Out[5]= {g[f[1]], g[f[2]], g[f[3]], g[f[4]]}
>
> (looks all nice in a Notebook)
>
>
>
> Robert
>


--
Murray Eisenberg murray@math.umass.edu
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