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Re: 0^0=1
Posted:
Apr 27, 2012 5:57 AM
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Dan Christensen wrote: > > [...] then x^1 = x only for non-zero x.
Not so. Your derivation relied on x not being zero, but that does not mean that one cannot prove x^1 = x without that restriction.
> Why should 0^1 be > acceptable with one starting point, but not another? Maybe x^0 = 1 for > all integers x is an acceptable starting point after all. Of course, > there is the problem with those limits as Virgil pointed out.
Limits don't come into it. What is under discussion is 0^0, _not_ the limit(s) of x^y.
-- When a true genius appears in the world, you may know him by this sign, that the dunces are all in confederacy against him. Jonathan Swift: Thoughts on Various Subjects, Moral and Diverting
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