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Re: 0^0=1
Posted:
May 6, 2012 6:25 PM
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LudovicoVan wrote:
>
> I have already explained that the exception for x=0 in x^0=x/x is a *new*
> condition.
What do you mean by new?
> I have also shown how from your recursive definition we still get x^0=x/x.
Only by being incapable of distinguishing n = 0 from n > 0.
--
When a true genius appears in the world, you may know him by
this sign, that the dunces are all in confederacy against him.
Jonathan Swift: Thoughts on Various Subjects, Moral and Diverting
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