Dr. Scales: Have never seen this approach before. Thanks. Ben
> Date: Sat, 19 May 2012 11:22:08 -0400 > From: firstname.lastname@example.org > To: email@example.com > Subject: Re: number of onto functions > > > Q: In how many ways can 7 different jobs be assigned > > to 4 different employees so that each employee gets > > atleast one job and the best employee gets the > > toughest job. > > > Mahesh, > > I tackled it this way: > > Let the 7 jobs be T(oughest) + 6 and > let the 4 employees be B(est) + 3 > > Then B and T always go together, plus 6 other jobs between 4 employees who always get at least 1 job each. > > Allocate 6 jobs one each to the other 3 employees in 6.5.4 ways, with 3 jobs over. > > Allocate these 3 jobs to 4 employees in 4.3.2 ways. > > So answer = 1 . 6.5.4 . 4.3.2 = 2880 I think. > > Regards, Peter Scales.