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Topic: Sets Forming Partitions
Replies: 6   Last Post: Oct 7, 2012 6:19 PM

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Posts: 17
From: Buffalo, NY
Registered: 9/30/12
Re: RE: Sets Forming Partitions
Posted: Oct 6, 2012 7:55 PM
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Ok so every number of S has to be in one of the sets as well for it to be a partition as well? Is that what you were getting at with (d.) so in this case now (d.) is not a partition of S.

Next the ordered pairs for (a.) would be:
(1,1), (3,3), (1,3), (3,1), (5,5), (4,4), (5,4), (4,5) (2,2), (6,6), (2,6), (6,2)?

Is this all correct?

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