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dwi
Posts:
17
Registered:
10/18/12


Re: sum of exponentials
Posted:
Nov 23, 2012 10:16 AM


"dwi" wrote in message <k8o2mg$pdp$1@newscl01ah.mathworks.com>... > "Roger Stafford" wrote in message <k8lqar$4po$1@newscl01ah.mathworks.com>... > > "dwi" wrote in message <k8l6sb$2fj$1@newscl01ah.mathworks.com>... > > > I have a matrix whose data are interrupted by sequences of zeros. I need every time that there's a zero value to substitute it with a sum of exponentials using the previous data, eg: > > > x=[x1 x2 x3 0 0 0 x7 0 0] > > > When i find the first zero in the element x4 I want: > > > x4=(x3*e^(1)+x2*e^(2)+x1*e^(3))/(e^(1)+e^(2)+e^(3)); > > > However, when I find the second zero value I need to calculate the same expression but without using the previous recalculated values. That is, > > > x4=x5=x6 > > > and for x8 I will use only the values in x7,x3,x2,x1 and then x8=x9 etc > > > And all this for a 180000length data. > > > Any ideas on how to do this? > > > Thanks in advance > >          > > a = 0; b = 0; > > for k = 1:length(x) > > if x(k) ~= 0 > > a = x(k) + a*e^(1); > > b = 1 + b*e^(1); > > else > > x(k) = a/b; > > end > > end > > > > Roger Stafford > Thank you for your answer but if I use this the index of the exponent never changes.I want it to decrease as k increases, and i don't know hot to calculate a sum like this.
A correction: x8=(x7*e^(1))/e^(1) ie without using x1,x2,x3 but only the immediate previous nonzero values



