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Topic: questions about a "proof" of the Goldbach Conjecture.
Replies: 4   Last Post: Nov 28, 2012 11:24 PM

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 forbisgaryg@gmail.com Posts: 43 Registered: 11/26/12
Re: questions about a "proof" of the Goldbach Conjecture.
Posted: Nov 27, 2012 3:24 AM

Thanks for the reply. I'm breaking usenet etiquette becuase
doesn't work on my machine and browser.

On Monday, November 26, 2012 10:08:44 AM UTC-8, christian.bau wrote:
> Here's something to think about:
>
> I'll call a set S of positive integers a "Goldbach set" if every even
> integer >= 4 is the sum of two elements of S.
> You can use "... if every even integer > 7 is the sum of two distinct
> elements of S".
>
> The Goldbach Conjecture now states that the set of primes is a
> "Goldbach set".
>
> Sets with many elements tend more to be Goldbach sets, while sets with
> fewer elements tend less to be Goldbach sets.
>
> However, a set can have an awful lot of elements and not be a Goldbach
> set: If you take S = the set of integers of the form 8k+1 and 8k+3,
> then no multiple of 8 is ever the sum of two elements of S. So your
> proof can't rely on the number of elements and sizes of gaps between
> elements alone. Your proof will have to have some element that
> actually uses the fact that S is a set of primes.
>
> Most "proofs" don't have a flaw that is easy to spot, they just don't
> contain anything that would be a proof. Someone said "this is so bad,
> it isn't even wrong". Many just assert that there are so many primes
> and so many possible sums, there _must_ be two primes adding up to
> that number. But assertion isn't proof. If you take the number 10^100,
> there are more than 10^97 primes < 5 * 10^99, so there are about 10^97
> numbers that would have to be composite to make 10^100 a counter
> example. It's very, very unlikely that all these 10^97 numbers are
> composite. But it's not impossible.

Thanks again.

Yes, The idea is to show why there can be no counter examples.
I don't see how one can just talk about the set of primes being
a Goldbach set and get anywhere. It seems important to talk
about the composite numbers relative to primes less than x/2
where x is an even number > 7 and how the primes involved in
those composite numbers rule out their pariticpation in the
composite number relative to other primes less than x/2. The
idea is to show that one runs out of primes that can participate
in composites prior to running out of primes.

So if one looks at the first 5 odd composite numbers, 9, 15, 21, 25,
and 27, that 3*3, 3*5, 3*3*3, 5*5, and 3*3*3*3, one can take
9 by itself. 9 + 3 makes 12 the first candidate even number that
might be a counter example but there are 2 primes less than 6 so
the next candidate even number is 18 but 9 is a multiple of 3
so every prime number offset from 9 by a multiple of 3 is also
met by a composite that is a multiple of 3 but there can be no
prime that is a multiple of 3. In fact 25 is the first odd composite
number that isn't a multiple of 3 so 28 is the first real candidate
counter example. 14 is a multiple of 7 so there will be no prime
that is a multiple of 7 and 28-7 is in fact a multiple of 7. The
only composites between 14 and 25 are the 15, 21, and 25 but there
are 5 primes less than 14.

primes because in order for 3, 5, 7 to be covered by composites
there must be a gap between primes big enough for all three to fit.
2x-7 must not be a multiple of 7, 2x-5 must not be a multiple of 5
and 2x-3 must not be a multiple of 3 otherwise 3,5, and 7 cannot
be included in the composites used to cover other primes because
there are no other primes that are multiples of these numbers.

As it turns out 95=19*5, 93=31*3, 91=7*13 so only 7 is excluded
from the composites of the first real counter example using less
naieve properties of the primes and what the form of a counter
example would look like. Well, since 95 is a multiple of 5 primes
that differ from 3 by a mutlple of 5 will be covered by a composite
that is a multiple of 5 as well, 98-13=85, 98-23=75, 98-43=45.
Likewise with primes that differ from 3 by multiples of 19, 98-41=57.
Well, the factors of the composites for 95, 93, and 91, nocked out
3, 5, 7, 11, 13, and 17 but not 19 so 79 is a matching prime or
it would have it's own composites not involving 3,5,7,13,19, or 31.

Anyway, I don't have the math skills yet to solve this problem.
Every composite knocks out at least one prime from future consideration
but the more primies involved in a composite the the more it knocks out
in future composites and the number of primes it knocks on starts to get
smaller the sooner the small primes get removed.

It seems to me the form of the proof is to show that there are more odd
primes less than some natural number greater than 3 than can be covered
by composites of the primes less than sqrt(2n).

Date Subject Author
11/26/12 forbisgaryg@gmail.com
11/26/12 gnasher729
11/27/12 forbisgaryg@gmail.com
11/28/12 locorodrigueztorres@gmail.com
11/28/12 forbisgaryg@gmail.com