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Topic:
Matheology S 162
Replies:
3
Last Post:
Nov 29, 2012 3:26 PM




Re: Matheology S 162
Posted:
Nov 28, 2012 1:46 PM


Pardon my lack of willpower. I once again feel compelled to point out that WM is a moron. It will do no good, I know.
WM <mueckenh@rz.fhaugsburg.de> writes:
> On 28 Nov., 16:13, William Hughes <wpihug...@gmail.com> wrote: >> On Nov 28, 10:59 am, WM <mueck...@rz.fhaugsburg.de> wrote: >> >> > On 28 Nov., 13:48, William Hughes <wpihug...@gmail.com> wrote: >> >> > > On Nov 28, 2:43 am, WM <mueck...@rz.fhaugsburg.de> wrote: >> >> > > > Induction proves also: Every set of natural numbers is finite. >> > > > Why do you overlook this simple proof? >> >> > > No, what induction proves is that every set of natural numbers >> > > with a largest number is finite. >> >> > And induction proves that every set of natural numbers has a largest >> > number. For every finite n also n + 1 is finite >> >> Look! Over There! A Pink Elephant! >> >> >and the set containing >> > both, n and n + 1 ist finite too. >> >> There is of course no such thing as >> "the set containing both n and n+1". > > Here it is: {n, n+1}
So, your conclusion is that, for every n, the set {n,n+1} is finite?
If so, surely we agree. And from this, we infer that every set of natural numbers is finite, er, how?
Fill in the gaps here:
For every n, the set {n, n+1} is finite.
.
.
.
Therefore, every set of natural numbers is finite.
 "Being in the ring of algebraic integers is just kind of being in a weird place, but it's no different than if you are in an Elk's Lodge with weird made up rules versus just being out in regular society."  James S. Harris, teacher



