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Re: Archimedes (and Ahmes) square root of 5, 6 and 7
Posted:
Dec 27, 2012 7:18 PM


Milo, I detect an error here.
"
(Q + R)^2, R= 1/(1/2Q)
step 1: estimated
Q = 2. R,= (1//4) such that try
(2 + 1/4)^2 = 6 + *(1/4)^2; error1 = 1/16 "
I believe it should be 5 + 1/4^2



