Virgil
Posts:
8,833
Registered:
1/6/11


Re: This Is a Failed *PROOF* that AD never produces a New Digit Sequence!
Posted:
Dec 30, 2012 12:39 AM


In article <1d297c9c4129474ab84e5f3cd0950803@p7g2000pbz.googlegroups.com>, Graham Cooper <grahamcooper7@gmail.com> wrote:
> On Dec 30, 1:15 pm, Virgil <vir...@ligriv.com> wrote: > > In article > > <c5b60ef52f844a6d811c373c2a3b1...@vb8g2000pbb.googlegroups.com>, > > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > > > > > > > > > > > > > > > > > On Dec 30, 9:31 am, Virgil <vir...@ligriv.com> wrote: > > > > In article > > > > <d95b3181537247ca8cc9f2d6ee9bb...@po6g2000pbb.googlegroups.com>, > > > > Graham Cooper <grahamcoop...@gmail.com> wrote: > > > > > > > AD METHOD (binary version) > > > > > Choose the number 0.a_1a_2a_3...., where a_i = 1 if the ith > > > > > number in your list had zero in its iposition, a_i = 0 otherwise. > > > > > > > LIST > > > > > R1= < <314><15><926><535><8979><323> ... > > > > > > R2= < <27><18281828><459045><235360> ... > > > > > > R3= < <333><333><333><333><333><333> ... > > > > > > R4= < <888888888888888888888><8><88> ... > > > > > > R5= < <0123456789><0123456789><01234 ... > > > > > > R6= < <1><414><21356><2373095><0488> ... > > > > > > .... > > > > > > > By breaking each infinite expansion into arbitrary finite length > > > > > segments > > > > > > > [3] The antiDiagonal never produces a unique segment > > > > > (all finite segments are computable) > > > > > > > [4] The antiDiagonal never produces a unique sequence > > > > > of segments (all segment sequences are computable) > > > > > > It easily produces a sequence which does not already exist in any > > > > countable seqeunce of sequences since it can be made to differ in at > > > > least one place with each sequence, the place depending on the listed > > > > position of that sequence. > > > > > > > It's just like the infinite STACK of ESSAYS! They contain every > > > > > possible sentence in every possible order! By changing one word at a > > > > > time it's Still IMPOSSIBLE to construct a New Essay! > > > > > > But your essays are all of finite length but each is a string of words > > > > taken from an infinite dictionary, which is not at all the same thing. > > > > > > Even so any infinite essay will differ from a of you essays, so you > > > > analogy fails. > > > > > NO VIRGIL! > > > > > You are MAKING UP BULLSHIT > > > > On the contrary, I am merely trying to dig myself out of yours. > > > > > If you disagree with a numbered point then which one? > > AD METHOD (binary version) > Choose the number 0.a_1a_2a_3...., where a_i = 1 if the ith > number in your list had zero in its iposition, a_i = 0 otherwise.
Which is correct for a list of infinite binary sequences, but the "list" below is not a list of infinite binary sequences to which the above can be applied.
> > LIST > R1= < <314><15><926><535><8979><323> ... > > R2= < <27><18281828><459045><235360> ... > > R3= < <333><333><333><333><333><333> ... > > R4= < <888888888888888888888><8><88> ... > > R5= < <0123456789><0123456789><01234 ... > > R6= < <1><414><21356><2373095><0488> ... > > .... > > By breaking each infinite expansion into arbitrary finite length > segments > > [3] The antiDiagonal never produces a unique segment > (all finite segments are computable)
Depends on what you call an antidiagonal. If R1(1) = <314>, R1(2) = <15>, R1(3) = <926>, ... And R2(1) = <27>, R2(2) = ,18281828>, R2(3) = <459045>, ... and so on, then any Roo such that Roo(1) <> R1(1), Roo(2) <> R2(2) and generally Roo(n) <> Rn(n) will be a sequence that is not listed in your listing.. > > [4] The antiDiagonal never produces a unique sequence > of segments (all segment sequences are computable)
But given any list of such sequences whose terms appear to be natural numbers, it is quite easy to show that there are such sequences not listed in that list.
Note that for two sequences to be equal, they must agree at EVERY position, not just a few positions. 

