Search All of the Math Forum:
Views expressed in these public forums are not endorsed by
Drexel University or The Math Forum.
|
|
|
|
Re: Subscripted dimension mismatch
Posted:
Jan 14, 2013 10:23 AM
|
|
"Jacob Moses" <jacobfmoses@gmail.com> wrote in message
news:kcs0nh$aav$1@newscl01ah.mathworks.com...
> Hello,
> I am attempting to separate a large matrix into two parts for kernel
> formation for clustering with a kernel k-means algorithm. While I would
> ordinarily jus reshape it into a third dimension, this option is
> impossible given that the number of columns in the matrix in question is
> odd (24021). I have been unable to perform any of the things that I have
> seen before, such as indexing. Below is the method I tried, which returned
> the above error message.
>
> EDU>> for n=1:24041
> if n<=12021
> split{1}(n)=test(:,n);
Unless test is a row vector, this won't work. The expression on the left of
the equals sign represents a scalar (a 1-by-1 chunk of split{1}) while the
expression on the right of the equals sign represents a size(test, 1)-by-1
chunk of data. The latter is too big to fit into the former unless as I said
size(test, 1) is 1.
> elseif n>12021
> split{2}(n-12021)=test(:,n)
Ditto.
> end
> end
> Subscripted assignment dimension mismatch.
>
> If anyone can tell me what is going on, I would greatly appreciate it.
> Thanks in advance.
There's no need for a loop here. Either:
1) If test is of odd length, pad it with a NaN then RESHAPE it. Otherwise
just RESHAPE it.
2) split{1} = test(:, 1:12021); split{2} = test(:, 12022:end);
If test may vary in size, you could use floor(end/2) in the second
expression to generalize it.
--
Steve Lord
slord@mathworks.com
To contact Technical Support use the Contact Us link on
http://www.mathworks.com
|
|
|
|
