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Virgil
Posts:
8,833
Registered:
1/6/11


Re: Calculating matrix permanent
Posted:
Jan 26, 2013 1:59 AM


In article <4491940f6d2b4afe9a24f2d1257a96c7@xm8g2000pbc.googlegroups.com>, "Patrick D. Rockwell" <prockwell@thegrid.net> wrote:
> On Jan 25, 9:13 pm, Virgil <vir...@ligriv.com> wrote: > > In article > > <3cd635d38c004c8fb5b3af9c45759...@v9g2000pbi.googlegroups.com>, > > "Patrick D. Rockwell" <prockw...@thegrid.net> wrote: > > > > > > > > > > > > > I've read how to calculate the permanent of a matrix, > > > but I found the notation hard to understand so I'd > > > Like a practical demonstration. For 2 by 2 matrices > > > It's easy. For example, the permanent of > > > > > 2 4 > > > 9 6 > > > > > Is 2*6+4*9=36+12=48 > > > > > But what about > > > > > 5 3 1 > > > 8 2 4 > > > 7 9 6 > > > > > What is48 the permanent of the above matrix > > > and how do you calculate it? > > > > What you have calculated for your 2 by 2 matrix is its DETERMINANT, > > not its "permanent". > > > > No, I believe that the determinate is > > 2*64*9 = 24 > > > See http://en.wikipedia.org/wiki/Determinant > > > > For more, including how tevaluate a 3 by 3 determinant. > >  > > The above article showed > me how to do th 2 by 2 case > but I just couldn't understand > The notation for the rest of it.
Oops! You are right about its not being the determinant, but googling for the permanent of a matrix will get you to http://en.wikipedia.org/wiki/Computing_the_permanent. and over 30 million other mostly relevant URLs 



