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can photons behave like electrons in AC current Chapt15.34 explaining Superconductivity from Maxwell Equations #1179 New Physics #1299 ATOM TOTALITY 5th ed
Jan 27, 2013 6:09 AM
Of the top ten toughest challenges of science that I have had to wrestle with, superconductivity is certainly among those top ten.
The last few days, I have hunted down some facts. I wanted to see how close the displacement current magnitude was to the resistivity of silver and mercury. I was playing the idea that zero resistance for mercury at 4 K is due to applied current + self induced current from the temperature gradient.
A typical displacement current is about 130mA as seen from a problem set in Halliday & Resnick, page 837, of Fundamentals of Physics, 1988.
I looked up what Onnes in 1911 used as a current for his superconductivity of mercury and he used a 0.6 A magnetic induced current.
I did some checking around and that superconductivity for zero resistance must be DC current and cannot be AC current. Again, my complaint is that I cannot solve superconductivity, unless I know the proper truthful facts. So much of the literature is obfuscation of the true properties of superconductivity.
So I am dismissing the idea that I need an extra current, a self induced current involving dB/dK.
What I end up with is where I started with the Ohm's law and a Malus law replacement of the R term in Ohm's law.
In other words, I now am more confident than before that this formula solves superconductivity:
V = i*R (Ohm's law
I' = I" cos^2(A) (Malus law)
Replacing R with Malus law and we have:
V = i * (I" cos^2(A))
Now, let me play some more around the concept of voltage.
If we look up AC current and find out the difference between it and DC current, we find it simply means the charge carriers move back and forth in AC, and move in only forward direction in DC. Now that understanding gives us a major clue as to what the role of photons are in electricity. The photons are what signals all the charge carriers in the wire circuit to move forward and then to move backward. It must be photons because the speed of AC and DC are the same speed of electricity-- the speed of light.
So the photons are responsible for the AC current as the messengers. And thus Malus law applies. And thus, since the Malus law applies, the Malus law causes some photons to be lost and thus resistivity occurs. If the wire circuit is polarized with a cosine of 0 degrees, then all the photons get through to tell the electrons to move and thus 0 resistance.
So a superconductor is a polarizer of 0 degrees.
Now let me also remark about Voltage in physics. Because if the photons are the messengers that tell electrons to move forward or move backwards at the speed of light, then AC current is pretty much what voltage is. For if a electron at the junction of the AC circuit, the end of the circuit, then the electron is at one moment in time moving forward and then the next moment moving backwards is the same as emf, or electromotive force or voltage.
And that idea agrees with Ohm's law:
V= i*R for we have this:
speed of light = electron speed * resistance
or we have this:
speed of light/ speed of electron = resistance
And we all know that electrons can travel up to 90% or even 99% of the speed of light (never at 100% but very close to it).
So what I am discovering is that voltage is really a term that means photons moving at the speed of light that creates a potential difference in the electric circuit.
In summary, I am back with the idea that superconductivity is merely the Malus law in the Ohm's law and that superconductivity is really a very simple and not complex phenomenon.
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