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anyone
Posts:
15
Registered:
6/18/12
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Re: Half width
Posted:
Feb 5, 2013 6:46 PM
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On Tue, 05 Feb 2013 22:19:16 +0000, Ella wrote:
> Hi
>
> I'm trying to find the width at which a f(x,y) decays to half the
> amount, but I only have the falling edge of the peak so the fwhm
> technique has not worked.
>
> This is the data I have:
>
> x=0,5,10,15,20,25
>
>
y=0.0444512401742601,0.0480445047384081,0.0453828898867642,0.0151597496747229,0.0140085866219010,-0.00920381996325553
>
> The error I got when using
>
> a=fwhm(x,y)
>
> was :
> Pulse Polarity = Positive
> Attempted to access y(29); index out of bounds because numel(y)=28.
>
> Error in fwhm (line 32)
> while ((sign(y(i)-lev50) ==
> sign(y(i-1)-lev50)) & (i <= N-1))
>
> Error in data (line 114)
> xhalf=fwhm(RefDist1,Anom1)
If you got that function through the File Exchange you should contact the
author.
> ... sorry if this is a bit vague.
Try to be a bit clear.
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