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Re: Intersection between two cones
Posted:
Feb 7, 2013 3:17 AM
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"Doctor61" wrote in message <kevm5s$fnm$1@newscl01ah.mathworks.com>...
>
> I have actually thought about something like what you described, but I don't know how to implement it in matlab. I thought I can find the two circles at the same distance from origin and see if they have intersections. But I don't know how to do that. Based on what I have found so far, if t is the parameter then any point P on the circle is given by:
> P=Rcos(t)u? +Rsin(t)n? ×u? +c
> Where u is a unit vector from the centre of the circle to any point on the circumference; R is the radius; n is a unit vector perpendicular to the plane and c is the centre of the circle.
>
> So if I have u1,n1,c1 and u2,n2 and c2, then how can I find the intersection?
Let's assume the 2D circle (after projection on a plane) is centered at 0.
Let's work on (x,y) plane. The circle is radius R
You can rotate the coordinates in such way that the line is parallel to y-axis: { x = x0, y arbitrary }.
x0 is the distance of the line to circle center.
The intersection is
x = x0
y = sin(+/-acos(x0/R)) = +- R * sqrt(1 - (x0/R)^2)
If |x0| > |R| there is no intersection.
Just rotate back after finding a solution.
Bruno
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